∫f(x)dx = F(x) + C∫xⁿdx = xⁿ⁺¹/(n+1) + C (n ≠ -1)∫dx/x = ln|x| + C∫e^x dx = e^x + C∫a^x dx = a^x/ln(a) + C∫sinx dx = -cosx + C∫cosx dx = sinx + C∫sec²x dx = tanx + C∫cosec²x dx = -cotx + C
∫u dv = uv - ∫v duMake substitution to simplify integral.
∫ₐᵇ f(x)dx = F(b) - F(a)
Given general solution, eliminate constants.
dy/dx = f(x)g(y)dy/g(y) = f(x)dx
dy/dx = f(y/x)dy/dx + Py = QInequalities in two variables.
Common region satisfying all constraints.
a + b = (a₁+b₁)i + (a₂+b₂)j + (a₃+b₃)kka = ka₁i + ka₂j + ka₃k
a·b = |a||b|cosθa·b = a₁b₁ + a₂b₂ + a₃b₃
a × b = |a||b|sinθ n̂a × b = | i j k || a₁ a₂ a₃ || b₁ b₂ b₃ |
a·(b × c) = Volume of parallelepiped
(x-h)² + (y-k)² = r²y² = 4ax (horizontal)x² = 4ay (vertical)x²/a² + y²/b² = 1c² = a² - b²x²/a² - y²/b² = 1c² = a² + b²σ² = Σ(xᵢ - x̄)² / n (Population)s² = Σ(xᵢ - x̄)² / (n-1) (Sample)
σ = √Variance
x̄ = (n₁x̄₁ + n₂x̄₂) / (n₁ + n₂)
r = Σ(x-x̄)(y-ȳ) / √[Σ(x-x̄)² Σ(y-ȳ)²]
y on x: y - ȳ = r (σ_y/σ_x) (x - x̄)x on y: x - x̄ = r (σ_x/σ_y) (y - ȳ)
P(A) = n(A)/n(S)
P(A∪B) = P(A) + P(B) - P(A∩B)
P(A∩B) = P(A) × P(B|A)
P(A|B) = P(B|A) P(A) / P(B)
P(r) = nCᵣ pʳ qⁿ⁻ʳ